SOLUTION INFO
C++ · main.cpp
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode() : val(0), left(nullptr), right(nullptr) {}
* TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
* TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
* };
*/
class Solution {
public:
TreeNode* constructFromPrePost(vector<int>& preorder, vector<int>& postorder) {
int N = (int)preorder.size();
vector<int> ridx(N + 1);
for(int i = 0; i < N; ++i) ridx[postorder[i]] = i;
int idx = 0;
function<TreeNode*(int,int)> dfs = [&](int l, int r) -> TreeNode* {
if(l > r || idx >= N) return nullptr;
TreeNode *cur = new TreeNode(preorder[idx ++]);
if(l == r) return cur;
int x = ridx[preorder[idx]];
cur->left = dfs(l, x);
cur->right = dfs(x + 1, r - 1);
return cur;
};
return dfs(0, N - 1);
}
};
SOLUTION DESCRIPTION
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