SOLUTION INFO
C++ · main.cpp
class Solution {
public:
vector<int> lexicographicallySmallestArray(vector<int>& nums, int limit) {
int N = (int)nums.size();
vector<int> idx(N); iota(idx.begin(), idx.end(), 0);
sort(idx.begin(), idx.end(), [&](int u, int v) -> bool { return nums[u] < nums[v]; });
vector<vector<int>> G;
G.emplace_back(); G.back().push_back(idx[0]);
for(int i = 1; i < N; ++i) {
if(nums[idx[i]] - nums[G.back().back()] > limit) G.emplace_back();
G.back().push_back(idx[i]);
}
vector<vector<int>> seq = G;
vector<int> answer(N);
for(int i = 0; i < (int)seq.size(); ++i) {
sort(seq[i].begin(), seq[i].end());
for(int j = 0; j < (int)seq[i].size(); ++j) answer[seq[i][j]] = nums[G[i][j]];
}
return answer;
}
};
SOLUTION DESCRIPTION
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