Baekjoon #2178

Baekjoon #2178

1개의 풀이 · C++

문제 원문 보기 ↗

SOLUTION INFO

C++ · main.cpp

main.cpp
#include <bits/stdc++.h>
using namespace std;

int dx[4] = {0, 0, -1, 1};
int dy[4] = {-1, 1, 0, 0};
int N, M;
string board[105];
int dist[105][105];

bool valid(int x, int y) {
    return 0 <= x && x < N && 0 <= y && y < M;
}

int main() {
    cin.tie(nullptr);
    ios::sync_with_stdio(false);
    cin >> N >> M;
    for (int i = 0; i < N; ++i) cin >> board[i];
    memset(dist, -1, sizeof(dist));
    queue<pair<int, int>> q;
    q.push({0, 0});
    dist[0][0] = 1;
    while (!q.empty()) {
        pair<int, int> p = q.front();
        int x = p.first;
        int y = p.second;
        q.pop();
        for (int i = 0; i < 4; ++i) {
            int nx = x + dx[i];
            int ny = y + dy[i];
            if (!valid(nx, ny)) continue; // out of bound
            if (board[nx][ny] == '0') continue; // blocked
            if (dist[nx][ny] != -1) continue; // already visited
            dist[nx][ny] = dist[x][y] + 1;
            q.push({nx, ny});
        }
    }
    cout << dist[N - 1][M - 1] << '\n';
    return 0;
}

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