SOLUTION INFO
C++ · main.cpp
#include<bits/stdc++.h>
using namespace std;
int dx[4] = {0, 0, -1, 1};
int dy[4] = {-1, 1, 0, 0};
int a[10][10];
bool vis[10][10];
int N, M;
vector<pair<int,int>> empty_cell;
int ans;
bool valid(int x, int y) {
return 0<=x && x<N && 0<=y && y<M;
}
void dfs(int idx, int cnt) {
if(cnt == 3) {
queue<pair<int,int>> q;
memset(vis, false, sizeof(vis));
for(int i=0;i<N;++i) {
for(int j=0;j<M;++j) {
if(!vis[i][j] && a[i][j] == 2) {
queue<pair<int,int>> q;
q.push({i, j});
vis[i][j] = true;
while(!q.empty()) {
int x = q.front().first;
int y = q.front().second;
q.pop();
for(int k=0;k<4;++k) {
int nx = x + dx[k];
int ny = y + dy[k];
if(!valid(nx, ny) || vis[nx][ny]) continue;
if(a[nx][ny] == 1) continue;
vis[nx][ny] = true;
q.push({nx, ny});
}
}
}
}
}
int safe = 0;
for(int i=0;i<N;++i) {
for(int j=0;j<M;++j) {
if(!vis[i][j] && a[i][j] == 0) ++safe;
}
}
ans = max(ans, safe);
return ;
}
if(idx == empty_cell.size()) return ;
int x = empty_cell[idx].first;
int y = empty_cell[idx].second;
a[x][y] = 1;
dfs(idx+1, cnt+1);
a[x][y] = 0;
dfs(idx+1, cnt);
}
int main() {
cin.tie(nullptr); ios::sync_with_stdio(false);
cin >> N >> M;
for(int i=0;i<N;++i) {
for(int j=0;j<M;++j) {
cin >> a[i][j];
if(a[i][j] == 0) empty_cell.emplace_back(i, j);
}
}
dfs(0, 0);
cout << ans << '\n';
return 0;
}
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